#include /** * https://leetcode-cn.com/explore/interview/card/top-interview-questions-easy/1/array/22/ * 买卖股票的最佳时机 II */ int main() { int val[] = {2, 1, 2, 0, 1}; int max = 0; for (int i = 1; i < sizeof(val) / 4; i++) { int d = val[i] - val[i - 1]; if (d > 0) { max += d; } } return max; }