init commit

archive/algorithm/leetcode/vhw.c

@@ -0,0 +1,144 @@
+#include <stdio.h>
+#include <string.h>
+#include <stdlib.h>
+#include <math.h>
+/**
+ * 验证回文字符串
+ * https://leetcode-cn.com/explore/interview/card/top-interview-questions-easy/5/strings/36/
+ */
+#define bool int
+#define true 1
+#define false 0
+bool isPalindrome(char *s)
+{
+    int len = strlen(s);
+    if (len < 1)
+    {
+        return true;
+    }
+    for (int start = 0, end = len - 1; start < end; start++, end--)
+    {
+        while (start < end) //遇到我们要判断数字字母的停止
+        {
+            if ((s[start] >= 48 && s[start] <= 57) ||
+                (s[start] >= 97 && s[start] <= 122))
+            {
+            }
+            else if (s[start] >= 65 && s[start] <= 90)
+            {
+                s[start] |= 32; //转换为小写
+            }
+            else
+            {
+                start++;
+                continue;
+            }
+            break;
+        }
+        while (start < end) //结束的同上
+        {
+            if ((s[end] >= 48 && s[end] <= 57) ||
+                (s[end] >= 97 && s[end] <= 122))
+            {
+            }
+            else if (s[end] >= 65 && s[end] <= 90)
+            {
+                s[end] |= 32; //转换为小写
+            }
+            else
+            {
+                end--;
+                continue;
+            }
+            break;
+        }
+        if (start >= end)
+        {
+            break;
+        }
+        if (s[start] != s[end])
+        {
+            return false;
+        }
+    }
+    return true;
+}
+/*
+int is_char(char c)
+{
+  return ( (c>='a' && c<='z') || (c>='A' && c<='Z') );
+}
+
+int is_num(char c)
+{
+  return (c>='0'&&c<='9');
+}
+
+int is_equal(char c1,char c2){
+  if(is_num(c1))
+    return c1 == c2; 
+  else//c1 is charactrer
+  {
+    if(is_num(c2))
+      return 0;
+    
+    c1 = c1  > 96 ? c1-32:c1;
+    c2 = c2  > 96 ? c2-32:c2;
+        
+    return c1 == c2; 
+  }
+
+}
+
+int isPalindrome(char* s) {
+  int len;
+  if(s == NULL || (len = strlen(s)) == 0)
+    return 1;
+
+  char *p = s;
+  char *q = s + len-1;
+
+  while(p < q)
+  {
+    if((!is_num(*p)) && (!is_char(*p)))
+    {   
+      p = p + 1;
+      continue;
+    }   
+
+    if((!is_num(*q)) && (!is_char(*q)))
+    {   
+      q = q - 1;
+      continue;
+    }   
+
+    if(is_equal(*p,*q) == 0)
+      return 0;
+
+    p = p + 1;
+    q = q - 1;
+  }
+  return 1;
+}
+*/
+void print_r(int *a, int len)
+{
+    for (int i = 0; i < len; i++)
+    {
+        printf("%d\t", a[i]);
+    }
+    printf("\n");
+}
+
+int main()
+{
+    char a[] = "A man, a plan, a canal: Panama";
+    printf("%d\n", isPalindrome("qwewq"));
+    printf("%d\n", isPalindrome(a));
+    printf("%d\n", isPalindrome("race a car"));
+    char b[] = "A man\r\na plan\r\na canal: Panama";
+    printf("%d\n", isPalindrome(b));
+    printf("%d\n", isPalindrome(".,"));
+    getchar();
+    return 0;
+}