feat 优先级规则按订阅和搜索拆分

This commit is contained in:
jxxghp
2023-09-19 21:40:36 +08:00
parent 2250e7db39
commit 1799b63abb
6 changed files with 61 additions and 17 deletions

View File

@ -169,31 +169,33 @@ def latest_version(_: schemas.TokenPayload = Depends(verify_token)):
return schemas.Response(success=False)
@router.get("/ruletest", summary="过滤规则测试", response_model=schemas.Response)
@router.get("/ruletest", summary="优先级规则测试", response_model=schemas.Response)
def ruletest(title: str,
subtitle: str = None,
ruletype: str = None,
db: Session = Depends(get_db),
_: schemas.TokenPayload = Depends(verify_token)):
"""
过滤规则测试,规则类型 1-订阅2-洗版
过滤规则测试,规则类型 1-订阅2-洗版3-搜索
"""
torrent = schemas.TorrentInfo(
title=title,
description=subtitle,
)
if ruletype == "2":
rule_string = SystemConfigOper().get(SystemConfigKey.FilterRules2)
rule_string = SystemConfigOper().get(SystemConfigKey.BestVersionFilterRules)
elif ruletype == "3":
rule_string = SystemConfigOper().get(SystemConfigKey.SearchFilterRules)
else:
rule_string = SystemConfigOper().get(SystemConfigKey.FilterRules)
rule_string = SystemConfigOper().get(SystemConfigKey.SubscribeFilterRules)
if not rule_string:
return schemas.Response(success=False, message="过滤规则未设置!")
return schemas.Response(success=False, message="优先级规则未设置!")
# 过滤
result = SearchChain(db).filter_torrents(rule_string=rule_string,
torrent_list=[torrent])
if not result:
return schemas.Response(success=False, message="不符合过滤规则!")
return schemas.Response(success=False, message="不符合优先级规则!")
return schemas.Response(success=True, data={
"priority": 100 - result[0].pri_order + 1
})